⑴ java中如何隨機產生一個指定數組中的數
1、獲取數組長度
intarr[]={1,2,3,4,5};//定義一個數組
intlen=arr.length;//獲取數組長度給變數len
2、根據數組長度,使用Random隨機數組的索引值
Randomrandom=newRandom();//創建隨機對象
intarrIdx=random.nextInt(len-1);//隨機數組索引,nextInt(len-1)表示隨機整數[0,(len-1)]之間的值
3、根據隨機索引獲取數組值
intnum=arr[arrIdx];//獲取數組值
⑵ java判斷數組中相同字元串的個數
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;
public class GetNum {
public static void main(String[] args) {
int a[]={2007,2008,2006,2004,1984,2007,2006,2006};
List<Num> list=new ArrayList<Num>();
for(int i=0;i<a.length;i++){
if(!isExist(a[i],list)){
Num n=new Num();
n.num=a[i];
n.n=1;
list.add(n);
}
}
for(Iterator<Num> it=list.iterator();it.hasNext();){
Num nu=it.next();
System.out.println(nu.num+":"+nu.n);
}
}
public static boolean isExist(int num,List<Num> list){
boolean b=false;
for(Iterator<Num> it=list.iterator();it.hasNext();){
Num nu=it.next();
if((nu.num==num)){
nu.n++;
b=true;
break;
}
}
return b;
}
}
class Num{
public int num;
public int n;
}
都說了是整形數組了..還用字元串進行比較呀!!!
呵呵...
祝樓主早日成功哈!!!!
⑶ Java中的數組中的數據如何使用例如判定一個數組里大於60,70,80的數值各有幾個。
比如有個數組 名為 arry
int index=0;
for(int i=0;i<arry.lenth;i++){
if(arry[i]>60){ // 從arry[0]開始循環,如果第i個數大於60. index就加1
index++;
}
}
循環結束, 輸出index就知道這個數組中有多少個數大於60了
⑷ 在Java中,如何檢測一個數組中是否包含某一個數據
在Java中,檢測一個數組是否包含某一個數據,通常有四種方法:
(1)for循環
(2)轉換為List,調用Arrays.asList(arr).contains方法
(3)使用Set
(4)使用Arrays.binarySearch()方法
下面為上述四種方法的具體代碼實現:
1、使用for循環
publicstaticbooleanuseLoop(String[]arr,StringtargetValue){
for(Strings:arr){
if(s.equals(targetValue))
returntrue;
}
returnfalse;
}
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2、轉換為List,調用Arrays.asList(arr).contains方法
publicstaticbooleanuseList(String[]arr,StringtargetValue){
returnArrays.asList(arr).contains(targetValue);
}
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3、使用Set
publicstaticbooleanuseSet(String[]arr,StringtargetValue){
SetStringset=newHashSetString(Arrays.asList(arr));
returnset.contains(targetValue);
}
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4、使用Arrays.binarySearch()方法
特別說明:binarySearch()二分查找僅適用於有序數組,如果不是有序數組,則報異常
(String[]arr,StringtargetValue){
inta=Arrays.binarySearch(arr,targetValue);
if(a0){
returntrue;
}else{
returnfalse;
}}
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(4)判斷java數組裡面的個數擴展閱讀:
Java種List列表的contains方法:
該方法是通過遍歷集合中的每一個元素並用equals方法比較是否存在指定的元素。
publicbooleancontains(Objecto){
IteratorEit=iterator();
if(o==null){
while(it.hasNext())
if(it.next()==null)
returntrue;
}else{
while(it.hasNext())
if(o.equals(it.next()))
returntrue;
}
returnfalse;
}
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⑸ 請問在java數組中怎麼判斷奇數偶數的個數
intmun[]={1,2,3,4,5,6,7,8,9};
intcount=0;
for(inti=0;i<mun.length;i++){
if(mun[i]!=0&&mun[i]%2==0)//0除外,能被2整除的數就是偶數
count++;
}
System.out.println("偶數有:"+count+"個");