在JAVA裡面使用JsonUtils.object2JsonString 將object轉換成JSON
在JS中使用var myObject = eval('(' + myJSONtext + ')'); 將JSON轉換成object
② 求這個json 的解析 需要建立 javabean
public class A{
public boolean boo;
List<B> username;
public class B{
public boolean boo;
public String name;
}
}
用gson解析吧，
public static <T> T getJsonToBean(String json, Class<T> clazz) {
if (json != null && clazz != null) {
Gson gson = new Gson();
return gson.fromJson(json, clazz);
}
return null;
}
A a= getJsonToBean(json,A.class);
③ 這種JSON的javabean怎麼寫用gson解析的.
Class
JsonBean
加get/setter方法,gson只認實體的屬性是否與傳回來的json的屬性名對應
④ json怎麼轉javabean
{
"animals":{
"dog":[
{"name":"Rufus","breed":"labrador","count":1,"twoFeet":false},
{"name":"Marty","breed":"whippet","count":1,"twoFeet":false}
],
"cat":{"name":"Matilda"}
}
}
⑤ 求助 這種json怎麼解析 javabean該怎麼寫
你這個JSON格式，就是數組裡面放數組，所以是，取JSON對象》取JSON數組data》取JSON數組。
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import java.util.ArrayList;
import java.util.Iterator;
import net.sf.json.*;
public class MainClass {
/**
* @param args
*/
public static void main(String[] args) {
JSONObject jsonObj = JSONObject.fromObject(JsonData.getData());
JSONArray jsonArr = jsonObj.getJSONArray("data");
Iterator<JSONArray> itr = jsonArr.iterator();
JSONArray temp;
while(itr.hasNext()) {
temp = itr.next();
System.out.println("===========Each JSONArray=========");
for(int i = 0; i<temp.size(); i++) {
System.out.println(temp.get(i));
}
}
}
private static class JsonData {
private static String getData() {
return "{\"data\":[[5000235,2,3441,8,17,\"北京測試\",\"10000101111\",\"\",\"\",\"100001\",\"\",\"2011-09-23 17:20:07\",18,\"vhcDefaultPwd\",1,0,\"2011-09-20 00:00:00\",12,0,380,\"測試\",213,1,0,0,0,0,0,\"2012-11-05 14:35:23\",\"\"],[5000236,27,3442,10,17,\"北京測試2\",\"1230000\",\"\",\"\",\"2010920002\",\"111111\",\"2011-09-23 17:20:08\",18,\"vhcDefaultPwd\",1,0,\"2011-09-20 00:00:00\",12,0,380,\"測試2\",213,1,0,0,0,0,0,\"2012-11-05 14:35:23\",\"\"]]}";
}
}
}
⑥ json為什麼解析為javabean
FastJson效率最高，是阿里巴巴開源 的Json處理工具包，包括「序列化」和「反序列化」兩部分，它具備如下特徵：
速度最快，測試表明，fastjson具有極快的性能，超越任其他的Java Json parser。包括自稱最快的JackJson；
功能強大，完全支持Java Bean、集合、Map、日期、Enum，支持范型，支持自省；無依賴，能夠直接運行在Java SE 5.0以上版本；支持Android；
⑦ Java解析json數據
JSONObject dataJson=new JSONObject("你的抄Json數據「);
JSONObject response=dataJson.getJSONObject("response");
JSONArray data=response.getJSONArray("data");
JSONObject info=data.getJSONObject(0);
String province=info.getString("province");
String city=info.getString("city");
String district=info.getString("district");
String address=info.getString("address");
System.out.println(province+city+district+address);
⑧ javabean轉json字元串
報什麼異常，有沒有debug過
obj為TUser生成的對象。。。。
object不是應該是一個時間的對象嗎
⑨ Json 轉 JavaBean
你好，舉個例子：
public class WhatBean {
private int x = 1;
private String userId = "112";
private List<Element> element;
public int getX() {
return x;
}
public void setX(int x) {
this.x = x;
}
public String getUserId() {
return userId;
}
public void setUserId(String userId) {
this.userId = userId;
}
public List<Element> getElement() {
return element;
}
public void setElement(List<Element> element) {
this.element = element;
}
}
public class Element {
private int id;
private String name;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
String jsonStr = "{x:1,\"userId\":\"112\",element:[{id:'123',name:'haha'},{id:'456',name:'hehe'}]}";
Map<String,Class<?>> m = new HashMap<String,Class<?>>();
m.put("x", Integer.class);
m.put("userId", String.class);
m.put("element",Element.class);
WhatBean whatBean = (WhatBean)JSONObject.toBean( JSONObject.fromObject(jsonStr), WhatBean.class, m );
for(Element e : whatBean.getElement()){
System.out.println(e.getId() +"," + e.getName());
}
⑩ 復雜的JSON怎麼轉換為JavaBean
必先創建一個java bean
publicclassStudent{
privateStringstudentName;
privateintstudentAge;
publicStringgetStudentName(){
tName;
}
publicvoidsetStudentName(StringstudentName){
this.studentName=studentName;
}
publicintgetStudentAge(){
returnstudentAge;
}
publicvoidsetStudentAge(intstudentAge){
this.studentAge=studentAge;
}
@Override
publicStringtoString(){
return"Student[studentName="+studentName+",studentAge="+studentAge+"]";
}
}添加fastjson 相關依賴，如果是maven 工程pom 添加
<dependency>
<groupId>com.alibaba</groupId>
<artifactId>fastjson</artifactId>
<version>1.2.56</version>
</dependency>
轉換過程如下：
StringjsonStr="{"data":{"Student":[{"studentName":"lily","studentAge":12}]}}";
//先轉換為map
Mapmap=(Map)JSONObject.parse(jsonStr);
MapstudentMap=(Map)map.get("data");
//Student後面對應一個對象數組。轉換方式如下。
ArrayList<Student>parseObject=JSON.parseObject(studentMap.get("Student").toString(),newTypeReference<ArrayList<Student>>(){});
System.out.println(parseObject);