16x64点阵滚动显示程序

❶ 单片机16*64点阵

/*-- 文字: 扬 --*/
/*-- 宋体12; 此字体下对应的点阵为：宽x高=16x16 --*/
0x10,0x00,0x11,0xF8,0x10,0x10,0x10,0x20,0xFC,0x40,0x10,0x80,0x11,0xFE,0x14,0x92,
0x18,0x92,0x30,0x92,0xD1,0x12,0x11,0x22,0x12,0x22,0x14,0x42,0x50,0x94,0x21,0x08,

/*-- 文字: 州 --*/
/*-- 宋体12; 此字体下对应的点阵为：宽x高=16x16 --*/
0x10,0x04,0x10,0x84,0x10,0x84,0x10,0x84,0x10,0x84,0x54,0xA4,0x52,0x94,0x52,0x94,
0x90,0x84,0x10,0x84,0x10,0x84,0x10,0x84,0x20,0x84,0x20,0x84,0x40,0x04,0x80,0x04,

❷ 求51单片机驱动16X64点阵，行列用74HC595芯片驱动的程序

这是的，自己一改就好了

//74HC595练习程序
//串入并出实现16流水灯效果
//2009.12.28
#include"reg52.h"
sbit shcp=P2^0; //数据在上升沿进入移位寄存器
sbit date1=P2^1; //串行数据输入端
sbit clock=P2^2; //上升沿时将数据输出到并行端口

unsigned char tab[]={0x7f,0xbf,0xdf,0xef,0xf7,0xfb,0xfd,0xfe,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff};
unsigned char tab1[]={0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f,0xbf,0xdf,0xef,0xf7,0xfb,0xfd,0xfe};

void delay(unsigned int delay)
{
unsigned char i;
for(;delay>0;delay--)
for(i=0;i<125;i++);
}

void send_data(unsigned char date) //发送数据
{
unsigned char i;
for(i=0;i<8;i++) //把每一位数据移入寄存器
{
shcp=0;
date=date<<1;
date1=CY;
shcp=1;
delay(20);
}
}

void main()
{
unsigned char k;
for(k=0;k<16;k++)
{
send_data(tab[k]);
send_data(tab1[k]);
{clock=0;clock=1;};
}
}

❸ 单片机32*64点阵显示两排16*16的汉字的程序……

/*************************************
** Header:
** File Name: 16*16点阵滚动显示汉字
** Author:
** Date:
*************************************/
#include <AT89X52.H>
unsigned char code digittab[]={
0x40,0x04,0x47,0xC2,0x44,0x41,0x44,0x42,0xFE,0x7C,0x40,0x00,0x01,0xF2,0x7D,0x22,
0x49,0x22,0x49,0x22,0x4F,0xFE,0x49,0x22,0x49,0x22,0xFD,0x26,0x41,0xF3,0x00,0x00 /* qiang---竖直向下从左到右 */
};
unsigned char code lie[]={0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};
unsigned int timecount;
unsigned char cnta;
unsigned char cntb;
unsigned char k,i=0;
void main(void)
{
TMOD=0x01;
TH0=(65536-3000)/256;
TL0=(65536-3000)%6;
TR0=1;
ET0=1;
EA=1;
k=0;
while(1)
{;
}
}
void t0(void) interrupt 1 using 0
{
P0=0x00;
P2=0x00;
TH0=(65536-3000)/256;
TL0=(65536-3000)%6;
P1=lie[k];
k ;
if(k==16) k=0;
l ;
P0=digittab[i];/*此处和字模有关*/
i ;
P2=digittab[i];
i ;
if(i==32)
i=0 ;
}